calculus: Find ds/dt for s = (t - 1) / (t + 1)

[sunnshyne411]

I am new to calculus and I have been having a difficult time understanding the subject. I recently bought "Calculus for Dummies", and, while it's helping, I am still lost. I know that this question is relatively simple but I am having difficulty getting the correct answer.

Find ds/dt for s = (t - 1) / (t + 1)

This is what I have so far:

. . .ds/ds = d[(t - 1) / (t + 1)] / dt

. . . . . . . .= [(t + 1)(1) - (t - 1)(1)] / (t + 1)^2

. . . . . . . .= 0 / (t + 1)^2

Maybe someone can see where I have went wrong...? :shock:

 

[stapel]

[(t + 1)(1) - (t - 1)(1)] / (t + 1)^2 = 0 / (t + 1)^2

Your numerator is:

. . . . .(1)(t + 1) - (t - 1)(1)

. . . . .(t + 1) - (t - 1)

. . . . .t + 1 - t + 1

. . . . .t - t + 1 + 1

How did you get this to be zero...?

Thank you.

Eliz.

 

[sunnshyne411]

Making silly mistakes will screw you up every time.

thanx

Eliz