i need help evaluating the integral ? x^4 - X^3/ X^2 dx
V venialove Junior Member Joined Mar 30, 2008 Messages 53 Mar 30, 2008 #1 i need help evaluating the integral ? x^4 - X^3/ X^2 dx
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Mar 30, 2008 #2 Re: calculus Simplify it, then it's a very easy antiderivative to find. Is that \(\displaystyle \frac{x^{4}-x^{3}}{x^{2}}\). If so, it simplifies down to something rather benign.
Re: calculus Simplify it, then it's a very easy antiderivative to find. Is that \(\displaystyle \frac{x^{4}-x^{3}}{x^{2}}\). If so, it simplifies down to something rather benign.
D Deleted member 4993 Guest Mar 30, 2008 #3 venialove said: i need help evaluating the integral ? x^4 - X^3/ X^2 dx Click to expand... The advice given above applies to the following also: \(\displaystyle x^4\, - \, \frac{x^3}{x^2}\) Just take the common factors (of the numerator and the denominator) out and cancel (in either case) to simplify
venialove said: i need help evaluating the integral ? x^4 - X^3/ X^2 dx Click to expand... The advice given above applies to the following also: \(\displaystyle x^4\, - \, \frac{x^3}{x^2}\) Just take the common factors (of the numerator and the denominator) out and cancel (in either case) to simplify
