calculus 3 math problem: evaluate double integral D (2xy/(x^2+y^2)dxdy

[sandy]

evaluate double integral D (2xy/(x^2+y^2)dxdy, where D is the intersection of the annulus 1=<x^2+y^2=<2 with the second quadrant {x=<0, y=>} by changing to polar coordinates.

 

[sandy]

calculus 3 math problem

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evaluate double integral D (2xy/(x^2+y^2)dxdy, where D is the intersection of the annulus 1=<x^2+y^2=<2 with the second quadrant {x=<0, y=>} by changing to polar coordinates.

 

[Deleted member 4993]

evaluate double integral D (2xy/(x^2+y^2)dxdy, where D is the intersection of the annulus 1=<x^2+y^2=<2 with the second quadrant {x=<0, y=>} by changing to polar coordinates.

Where are you exactly stuck?

Have you drawn a sketch of the region under consideration?

Have you have converted x and y to r*sin(Θ) and y = cos(Θ) and correspondingly converted dx and dy?

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