How about the floor function?Can anyone think of a non-piecewise function that has a jump discontinuity?
I would say no, as it is defined as a piecewise function. I too thought of that but rejected it. For the record I have a very nice function. Nothing strange or fancy just a very clean looking function.How about the floor function?
Actually, have you tried formally defining the floor function piecewise? (It has infinitely many pieces!) I agree that it seems inherently piecewise; but I imagine that could be said about anything with a jump.I would say no, as it is defined as a piecewise function. I too thought of that but rejected it. For the record I have a very nice function. Nothing strange or fancy just a very clean looking function.
Should I post it now or does anyone want more time?
But that's undefined at x=0; I could be wrong, but I think of a jump discontinuity as being like all the other examples, which are defined at that point.f(x) = e^(1/x)/[1+e^(1/x)]
This will be my favorite function for a while.
https://www.wolframalpha.com/input/?i=graph+f(x)+=+e^(1/x)/[1+e^(1/x)]
[MATH]\frac x {\sqrt{x^2}}[/MATH]
These both share the difficulty that they are not defined at x=0; if you allow a jump discontinuity to be like that, then it's a lot easier to find examples.does arctan(1/x) fit?
graph f(x) = arctan(1/x) - Wolfram|Alpha
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Just to throw in a bit of uncertainty. I'm not convinced that it is a standard definition that a piecewise continuous function on an interval must be defined at each point of the interval. Look here for an example of that:
I don't know where to look for an "official" definition which is generally agreed.