Hello.
I am wondering if there is any method to calculate square root of Babylonian sexagesimal number (base 60) without converting it to base 10 and using Babylonian method for finding square roots.
Example is 3; 0, 56, 15
Thanks for your time reading and responding to my question and look forward to hearing back from you!
BomKem
-----------------------------------------------------------------
The below is normal steps is to figure out square root of base 60 number
3; 0, 56, 15 = ((15/60+56)/60+0)/60 + 3 = (56.25/60 + 0)/60 +3 = (0.9735+0)/60+3 = 3.015625 -------This is a base 60 to base 10 conversion
then using the Babylonian Method of finding square root, one can find the sqrt(3.015625 ) = 1.736555499
-----------------------------------------------------------------
I am wondering if there is any method to calculate square root of Babylonian sexagesimal number (base 60) without converting it to base 10 and using Babylonian method for finding square roots.
Example is 3; 0, 56, 15
Thanks for your time reading and responding to my question and look forward to hearing back from you!
BomKem
-----------------------------------------------------------------
The below is normal steps is to figure out square root of base 60 number
3; 0, 56, 15 = ((15/60+56)/60+0)/60 + 3 = (56.25/60 + 0)/60 +3 = (0.9735+0)/60+3 = 3.015625 -------This is a base 60 to base 10 conversion
then using the Babylonian Method of finding square root, one can find the sqrt(3.015625 ) = 1.736555499
-----------------------------------------------------------------