Please help me with these. I sort of solved them but I dont think I did it right because the answer choices seem different
1. Find all extreme values in the interval [0,2pi] for y = x - cosx
I found the derivative to be y' = 1 + sin x. Then I set it equal to zero and got sin x = -1, x = 3pi/2. What do I do from here? Do I find the value of f'(3pi/2) and f'(0) ? ::The answer choices are given like (-1,3pi/2) , (pi , 1+pi ) , (-1 , 0 ) , (3pi/2 , 2pi)::
2. Find the minimum value of the slope of the curve y = x^5 + x^3 - 2x
I found y' = 5x^4 + 3x^2 - 2
Now what do I do?
3. The motion of a particle is given by position function s(t) = t^3 - 6t^2 + 12t - 8
The minimum value of the speed is
Do I just find the derivative and then set it equal to 0? and then plug it in to determine which is the minimum?
I appreciate any help. Thank you!
1. Find all extreme values in the interval [0,2pi] for y = x - cosx
I found the derivative to be y' = 1 + sin x. Then I set it equal to zero and got sin x = -1, x = 3pi/2. What do I do from here? Do I find the value of f'(3pi/2) and f'(0) ? ::The answer choices are given like (-1,3pi/2) , (pi , 1+pi ) , (-1 , 0 ) , (3pi/2 , 2pi)::
2. Find the minimum value of the slope of the curve y = x^5 + x^3 - 2x
I found y' = 5x^4 + 3x^2 - 2
Now what do I do?
3. The motion of a particle is given by position function s(t) = t^3 - 6t^2 + 12t - 8
The minimum value of the speed is
Do I just find the derivative and then set it equal to 0? and then plug it in to determine which is the minimum?
I appreciate any help. Thank you!