calc help

SMITH4

New member
Joined
Jan 26, 2006
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8
just checking to see if i did this right

Find all values x = a where the function is discontinuous.

f(x) = | x^2 - 49 |
-----------------
x-9


i got a = 7, 9
 
\(\displaystyle \mbox{f(x) = \frac{|x^2 - 49|}{x - 9}}\) is defined at x=7 -- f(7)=0 (we're allowed to have a zero numerator with a non-zero denominator) -- and approaches 0 from either side.
 
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