calc: Find dr/dx for r = sqrt(x sin(x))

xc630

Junior Member
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Sep 1, 2005
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Hi I would appreciate any help with this derivative need to find

Find dr/dx

r = SQRT ( xsinx)

I rewrote it as (x sin x)^1/2

And proceeded as follows:

1/2 (x Sin X) ^-1/2

I think this only part of the next step. I'm not sure what I need to do also. Would appreciate any help. thanks
 
what do you know about the chain rule?

r = (xsinx)<sup>1/2</sup>

dr/dx = (1/2)(xsinx)<sup>-1/2</sup>(xcosx + sinx)

dr/dx = (xcosx + sinx)/[2(xsinx)<sup>1/2</sup>]
 
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