A baseball is thrown from the stands 32ft above the field at 30 degrees from horizontal. When and how far away will it land if the initial speed is 32ft/sec?
Vv = 32sinµ = 16
Vh = 32cosµ 27.7128
1--From Vf = Vo - gt, o = 16 - 32t1 making t1 = .5 sec.
2--From h = Vvt1 - 32t1^2/2, h1 = 16(.5) - 16(.5^2) = 4 ft.
3--From h2 = Vvt2 + 16t2^2, 36 = 0 + 16(t2^2 making t2 = 1.5sec.
4--WIth T = .5 + 1.5 = 2 sec., d = 2(32)cosµ = 55.42 ft.