Calc 3 question! Perpendicular surfaces

sergnio

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Show that the surfaces given by xy^5 + yz^5 + zx^5 = 3 and x^2 + y^2 = 2z^2 intersect in a perpendicular manner at (1,1,1).
I've been staring at this problem for over an hour, looking online, through my book, through my notes as to how to go about doing this and I have noo idea.
Thanks in advance!
 
Show that the surfaces given by xy^5 + yz^5 + zx^5 = 3 and x^2 + y^2 = 2z^2 intersect in a perpendicular manner at (1,1,1).
I've been staring at this problem for over an hour, looking online, through my book, through my notes as to how to go about doing this and I have noo idea.
Thanks in advance!

What are the normal and gradients of these surfaces at (1,1,1)?
 
Hm perhaps that's the first step to solving the problem.. (those are not given)
I tried finding the gradient, but I don't believe I calculated it properly.
 
The gradient to the first problem is {y^5 + 5 x^4 z, 5xy^4 + z^5, x^5 + 5t z^4}
and the gradient to the second is {2x, 2y, -4z}
Evaluate those two vectors at the point (1,1,1).

Are they perpendicular to each other at that point?
 
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