You could start by finding the equation of the plane which passes through the points (9,0,0), (0,8,0), (0,0,6)
The equation of this plane is \(\displaystyle 48x+54y+72z=432\).
Solved for z is \(\displaystyle z=\frac{-2x}{3}-\frac{3y}{4}+6\)
Therefore, the z limits of integration are 0 to \(\displaystyle z=\frac{-2x}{3}-\frac{3y}{4}+6\)
To find the y limits, set z=0 in the original plane equation and solve for y.
We get \(\displaystyle y=8-\frac{8x}{9}\)
The x limits are 0 to 9. They are given.
So, we have:
\(\displaystyle \int_{0}^{9} \;\ \int_{0}^{8-\frac{8x}{9}} \;\ \int_{0}^{\frac{-2x}{3}-\frac{3y}{4}+6}dzdydx\)
Once you have this result, compare it to the volume of a tetrahedron formula, \(\displaystyle V=\frac{1}{3}A_{0}h\)
Where \(\displaystyle A_{0}\) is the area of the base and h is the height. See if you get the same. You should.