Hi, how can i do this? \displaystyle b)\quad \int\, \sqrt{\strut 1\, -\, \sqrt{\strut x\,}\,}\, dx
H higopr New member Joined Jul 8, 2017 Messages 2 Jul 8, 2017 #1 Hi, how can i do this? \(\displaystyle \displaystyle b)\quad \int\, \sqrt{\strut 1\, -\, \sqrt{\strut x\,}\,}\, dx\) Attachments WhatsApp Image 2017-07-05 at 22.18.04.jpeg 4.3 KB · Views: 15 Last edited by a moderator: Jul 14, 2017
Hi, how can i do this? \(\displaystyle \displaystyle b)\quad \int\, \sqrt{\strut 1\, -\, \sqrt{\strut x\,}\,}\, dx\)
D Deleted member 4993 Guest Jul 8, 2017 #2 higopr said: Hi, how can i do this? \(\displaystyle \displaystyle b)\quad \int\, \sqrt{\strut 1\, -\, \sqrt{\strut x\,}\,}\, dx\) Click to expand... View attachment 8232 Substitute: u = [1-x^(1/2)]^(1/2) x = (1- u^2)^2 dx = ???.... and continue.... Last edited by a moderator: Jul 14, 2017
higopr said: Hi, how can i do this? \(\displaystyle \displaystyle b)\quad \int\, \sqrt{\strut 1\, -\, \sqrt{\strut x\,}\,}\, dx\) Click to expand... View attachment 8232 Substitute: u = [1-x^(1/2)]^(1/2) x = (1- u^2)^2 dx = ???.... and continue....
H higopr New member Joined Jul 8, 2017 Messages 2 Jul 8, 2017 #3 Subhotosh Khan said: View attachment 8232 Substitute: u = [1-x^(1/2)]^(1/2) x = (1- u^2)^2 dx = ???.... and continue.... Click to expand... Is this right?
Subhotosh Khan said: View attachment 8232 Substitute: u = [1-x^(1/2)]^(1/2) x = (1- u^2)^2 dx = ???.... and continue.... Click to expand... Is this right?
D Deleted member 4993 Guest Jul 9, 2017 #4 higopr said: Is this right? View attachment 8236 Click to expand... Differentiate you "answer" and check it out yourself!
higopr said: Is this right? View attachment 8236 Click to expand... Differentiate you "answer" and check it out yourself!