2-(1-x) = x+1
D Deleted member 4993 Guest Mar 7, 2010 #2 erlikprime said: 2-(1-x) = x+1 Click to expand... 2−(1−x)=2+(−1)∗(1−x)=2+(−1+x)=2−1+x=1+x\displaystyle 2 - (1 - x) = 2 + (-1) * (1 - x) = 2 + (-1 + x) = 2 - 1 + x = 1 + x2−(1−x)=2+(−1)∗(1−x)=2+(−1+x)=2−1+x=1+x
erlikprime said: 2-(1-x) = x+1 Click to expand... 2−(1−x)=2+(−1)∗(1−x)=2+(−1+x)=2−1+x=1+x\displaystyle 2 - (1 - x) = 2 + (-1) * (1 - x) = 2 + (-1 + x) = 2 - 1 + x = 1 + x2−(1−x)=2+(−1)∗(1−x)=2+(−1+x)=2−1+x=1+x
mmm4444bot Super Moderator Joined Oct 6, 2005 Messages 10,962 Oct 26, 2010 #5 queendiva_314 said: how do you [multiply] this -6(a+8) Click to expand... Apply the Distributive Property: A(B + C) = (A)(B) + (A)(C) In other words, each of the numbers inside the parentheses gets multiplied by the number in front of the parentheses. The number B gets multiplied by A, and the number C gets multiplied by A: AB + AC Can you see that the expression -6(a + 8) has the same form as the expression A(B + C) ? Apply the Distributive Property. Both numbers inside the parentheses (the number 'a' and the number 8) get multiplied by the factor in front (-6). PS: Please use the [NEWTOPIC] button on the board's index page (upper left area) to start your own thread, next time. Cheers
queendiva_314 said: how do you [multiply] this -6(a+8) Click to expand... Apply the Distributive Property: A(B + C) = (A)(B) + (A)(C) In other words, each of the numbers inside the parentheses gets multiplied by the number in front of the parentheses. The number B gets multiplied by A, and the number C gets multiplied by A: AB + AC Can you see that the expression -6(a + 8) has the same form as the expression A(B + C) ? Apply the Distributive Property. Both numbers inside the parentheses (the number 'a' and the number 8) get multiplied by the factor in front (-6). PS: Please use the [NEWTOPIC] button on the board's index page (upper left area) to start your own thread, next time. Cheers