Bracelets: how to join sets of links for $4, not $6

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Mustang1910

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* Suppose there is 3 sets of circles like the one attached*

Janet wants to join the three parts above into a bracelet. The jeweler says he has to charge $2 for each link he must cut and resauder. He figures it will cost $6. Janet figures out a way where it will cost $4. How?

I would really appreciate the hepl. Thanks!
 

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Mustang1910 said:
* Suppose there is 3 sets of circles like the one attached* Janet wants to join the three parts above into a bracelet. The jeweler says he has to charge $2 for each link he must cut and [resolder]. He figures it will cost $6. Janet figures out a way where it will cost $4. How?
Click to expand...
What are your thoughts? The puzzle points out, fairly obviously, that you only need to cut two of the links. What have you tried? How far have you gotten in following that directive?

Please be complete. Thank you! :D

Eliz.
 
Also, problem doesn't seem properly worded, since $2 will do it: 1 cut on the circle intended as middle circle;
then slip in the 2 other circles.
 
Denis said:
Also, problem doesn't seem properly worded, since $2 will do it: 1 cut on the circle intended as middle circle;
then slip in the 2 other circles.
Click to expand...
I think the original poster meant to say that there are three sets of links, each set containing one pair of links. That is, there are six links total, which are to be joined in one circle, but currently the links are in three sets of two conjoined links each.

I could be wrong, of course.... :oops:

Eliz.
 
At first glance one would probably think of cutting one of the links in each of the three pairs of links and join them together end to end. I think what is intended is that you cut both links in one pair and use those as "joining" links to join the other two pair to form the bracelet. The drawing implies the links are of different size, so for appearances, the first way would probably be desirable so that the bracelet would have every other link the same size. If the links are the same size, the second way would be quite acceptable.
 
Denis said:
...problem doesn't seem properly worded....
Click to expand...
stapel said:
I think the original poster meant to say....
I could be wrong, of course....
Click to expand...
Loren said:
At first glance one would probably think....
I think what is intended....
The drawing implies...the first way would probably be desirable....
If the links are the same size, the second way would be quite acceptable.
Click to expand...
Clarification would be helpful, Mustang1910. We await your positive participation.

popcorn.gif


Eliz.
 
I tried to find a image of circles the same size, however the original problem does have the bracelet links as all the same size. There are 3 images of the bracelet links (all the same size--for a total of 6 links--2 links in each bracelet are together). The problem does read: the jeweler says he has to charge $2 for each link he must cut and resauder. He figures it will cost $6. Janet figures out a way where it will cost $4. How?
 
So the exercise was as I described, and the solution was as Loren described. :D

Eliz.
 
Suppose there is 3 sets of circles like the one attached*

Janet wants to join the three parts above into a bracelet. The jeweler says he has to charge $2 for each link he must cut and resauder. He figures it will cost $6. Janet figures out a way where it will cost $4. How?

I would really appreciate the hepl. Thanks!

The 3 pairs of links are
AL-BS, CL-DS, and EL-FS where A, B, C, D, E and F identify the 6 links and L and S identify whether the link is small or large.

Cut links AL and BS.
Link DS to EL with AL and CL to FS with BS.
This costs $4.00 but produces an esthetically unpleasing bracelet.
 
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