RoseOfStone241
New member
- Joined
- Sep 5, 2006
- Messages
- 9
In my book this is the information given:
Angle BAC = 120 degrees, and points D, E, F are the interior of BAC. Ray AD bisects angle BAF, and ray AE bisects angle CAF. Find m of angle DAE.
Alright, so i think that's the best way to describe the diagram. BAC is obtuse and rays AD, AF, and AE are drawn from BAC's vertex of A.
Obviously BAD and DAF are congruent, and FAE and EAC are congruent.
Other than this info., I'm lost on where to begin.
Any help would be much appreciated ^-^
Angle BAC = 120 degrees, and points D, E, F are the interior of BAC. Ray AD bisects angle BAF, and ray AE bisects angle CAF. Find m of angle DAE.
Alright, so i think that's the best way to describe the diagram. BAC is obtuse and rays AD, AF, and AE are drawn from BAC's vertex of A.
Obviously BAD and DAF are congruent, and FAE and EAC are congruent.
Other than this info., I'm lost on where to begin.
Any help would be much appreciated ^-^