bionomial distribution

Clifford

Junior Member
Joined
Nov 15, 2006
Messages
81
A die is thrown 20 times. Use the bionomial distrubution to determine the probability of getting five successes in 20 trials, if rolling a 2 or a 4 is considered to be a success.

\(\displaystyle \[
\begin{}
p(5)\; = \;\left( \begin{}
N \hfill \\
k \hfill \\
\right)p^k (1 - p)^{N - k} \hfill \\
= \;\left( \begin{}
20 \hfill \\
5 \hfill \\
\right)\left( {\frac{1}
{3}} \right)^5 \left( {\frac{2}
{3}} \right)^{15} \hfill \\
= \;0.1457 \hfill \\

\]\)

The texaide doesn't seem to be working but the (Nk) should be NCk

Did I do this correctly?
 
Yes you did it correctly if it agrees with
\(\displaystyle \L \left( {\begin{array}{c}
{20} \\
5 \\
\end{array}} \right)\left( {\frac{1}{3}} \right)^5 \left( {\frac{2}{3}} \right)^{15}\)
 
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