Believe it or Not

I believe so. As we know, the sum of the first n integers is n(n+1)2\displaystyle \frac{n(n+1)}{2}

The sum of the first n cubes is given by n2(n+1)24\displaystyle \frac{n^{2}(n+1)^{2}}{4}

The latter is the square of the former.
 
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