Base e and Natural Logarithms

[jeybeyb]

2e^x - 3 =1
+3 +3
2e^x= 4 (divided both sides by 2)
lne^x = ln 2
x = .6931

Is this right? I'm not sure if I should've waited and divided 2 after doing the ln of 4.

 

[Mrspi]

2e^x - 3 =1
+3 +3
2e^x= 4 (divided both sides by 2)
e[sup:1gdjm98p]x[/sup:1gdjm98p] = 2
Then, take the natural log of both sides to get
lne^x = ln 2
x = ln 2
x = .6931

Is this right? I'm not sure if I should've waited and divided 2 after doing the ln of 4.

This looks fine...the steps I inserted are to clarify what is going on and to make sure that no step is "implied"