Bad Beat Jackpot: in a hypothetical scenario where there are only two people in the hand, how many bad beat qualifying hands...?

philipdooman

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I play poker at a casino in Pennsylvania where the bad beat Jackpot is over $500,000 right now. The criteria to hit the bad beat jackpot is that you need to have at least quad 5's (if you are using a pair to hit the bad beat) and lose the hand. both players must use both of their hole cards. Example: I have pocket 7's and my opponent has 6 9 of spades. The board runs out 5 spade, 7 spade, 7 diamond, 8 spade, 10 spade. My question is this: in a hypothetical scenario where there are only two people in the hand, how many bad beat qualifying hands would be "drawing dead" against other bad beat qualifying hands, and how many bad beat qualifying hands would be drawing live against other bad beat qualifying hands. I am making the assumption that the person that answers this question knows something about poker. I would greatly appreciate if someone could answer this question for me. Thank you!!!!
 
I play poker at a casino in Pennsylvania where the bad beat Jackpot is over $500,000 right now. The criteria to hit the bad beat jackpot is that you need to have at least quad 5's (if you are using a pair to hit the bad beat) and lose the hand. both players must use both of their hole cards. Example: I have pocket 7's and my opponent has 6 9 of spades. The board runs out 5 spade, 7 spade, 7 diamond, 8 spade, 10 spade. My question is this: in a hypothetical scenario where there are only two people in the hand, how many bad beat qualifying hands would be "drawing dead" against other bad beat qualifying hands, and how many bad beat qualifying hands would be drawing live against other bad beat qualifying hands. I am making the assumption that the person that answers this question knows something about poker. I would greatly appreciate if someone could answer this question for me. Thank you!!!!
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I really don't know how to go about solving this because I am not a mathmatician.
Ace 2 Ace 3, Ace 2 Ace 4, Ace 2 Ace 5, 2 3, 2 4, 2 5, 2 6, 3 4, 3 5, 3 6, 3 7, 4 5, 4 6, 4 7, 4 8, 5 6, 5 7, 5 8, 5 9, 6 7, 6 8, 6 9, 7 8, 7 9, 8 9, 9 10, 9 Jack, 9 Queen, 9 King, 10 Jack, 10 Queen, 10 King, 10 Ace, Jack Queen, Jack King, Jack Ace, Queen King, Queen Ace, King Ace.

All of these starting hands (suited) are bad beat qualifying hands. Every combination of the cards above is drawing dead to any combination of cards listed above of a different suit.

All pocket pairs are drawing dead against a suited combination involving one of the two cards. Example:

Jack Ten of Diamonds is drawing dead against pocket 10s or Jacks.

Starting hand is drawing dead vs starting hand

Ace 2 ace 3 Ace 4 Ace 5

Ace 3 Ace 4 Ace 5 Ace 6

Ace 4 Ace 5 Ace 6 Ace 7

Ace 5 Ace 6 Ace 7 Ace 8

Ace 6 Ace 7 Ace 8 Ace 9

Ace 7 Ace 8 Ace 9 Ace 10

Ace 8 Ace 9 Ace 10 Ace Jack

Ace 9 Ace 10 Ace Jack, Ace Queen

Ace 10 Ace Jack Ace Queen, Ace K


I started listing hands that individually would qualify for the bad beat, but against each other are drawing dead. I know that there is a way to calculate all the hands, but I have no idea how to do the calculation.
 
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