Axis of Symmetry of y=(x-3)^2 after shifting 4 left, 2 down

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beetay719

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May 27, 2007
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The graph of y=(x-3)^2 is shifted left 4 units and down 2 units. What is the axis of symmetry of the transformed graph?

I knew the axis of symmetry formula is x=-b/2a.
I thought about using a chart to graph the equation, and then shifting the points, but i don't see where I would get the axis of symmetry from that.

Help please?
 
Starting

y = (x-3)^2

Axis of symmetry: x = 3

Shift left 4

y = (x+1)^2

Axis of symmetry: x = -1

Shift down 2

y = (x+1)^2 - 2

Axis of symmetry: x = -1

Notice how a vertical shift doesn't change the axis of symmetry on this kind. If it were x = y^2, then the horizontal shift wouldn't do anything.
 
huh?

I'm totally lost.

How did u know what the equation was after u shifted it?
 
nevermind

I figured it out after looking at your help over and over! haha thanks very much!
 
-b/(2a) still works, but you must multiple everything out and simplfy in order to determine 'b'. 'a' is pretty easy. It ALWAYS helps to have more than one way to proceed.

Good work. Show us another one so we can see that you have it.
 
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