Average Velocity: car goes 300 mi in same time as bus goes

[Bubbles28]

A car can travel 300 miles in the same amount of time it takes a bus to travel 180 miles. If the average velocity of the bus is 20 miles per hour (mph) slower than the average velocity of the car, find the average velocity for the bus and the car.

Express your solutions as one of the following: a) an inequality using a variable, b) using interval notation, or c) graph the solution set on a number line.

 

[stapel]

A car can travel 300 miles in the same amount of time it takes a bus to travel 180 miles. If the average velocity of the bus is 20 miles per hour (mph) slower than the average velocity of the car, find the average velocity for the bus and the car.

The bus' rate of speed is defined in terms of the car's, so pick a variable for the car's rate.

Create an expression, in terms of this variable, for the rate of the bus.

Use "d = rt" to create expressions for the time each vehicle took. For instance, since d = rt and thus t = d/r, and since the car covered 300 miles at some rate "r", then the car's time was 300/r.

Since the times were equal, set the two "time" expressions equal to each other, and solve the resulting rational equation for the value of the variable.

Back-solve for the other rate of speed.

Note: Since the exercise asks for two numbers, I have no idea how you're expected to "express the solution" in the manners specified. :shock: