ave rate of change again

[veryconfused]

average rate of change for each function over the given interal

y=sqrt(3x-2) between x=1 and x=1.5

f(1) = sqrt(3*1-2) = 1

f(2) = sqrt(3*1.5-2) = 1.58


average rate of change formula (f(b)-f(a))/b-a

f(1.58)-f(1)/1.58-1

=-209/3950

am I close?

 

[Daniel_Feldman]

average rate of change for each function over the given interal

y=sqrt(3x-2) between x=1 and x=1.5

f(1) = sqrt(3*1-2) = 1

f(2) = sqrt(3*1.5-2) = 1.58 Huh?

You need (f(b)-f(a))/(b-a); a=1, b=1.5


average rate of change formula (f(b)-f(a))/b-a

f(1.58)-f(1)/1.58-1

=-209/3950

am I close?

 

[veryconfused]

y=sqrt3x-2 between x=1 and x=1.5

why would you not insert the 1.5 into the x for the second number (b) to make the interal the right one?

 

[tkhunny]

Your just a little confused.

You start out with b = 1.5.

Why did you change to b = f(1.5) = 1.5811??

 

[veryconfused]

Did I not need to break it down to f(a) and f(b)?

So basically the steps would be for the problem is

y=((sqrt)3(1.5)-2) - ((sqrt)3(1)-2) / 1.5-1

=((sqrt)4.5-2)-((sqrt)3-2) / 1.5-1

=((sqrt)2.5)-(sqrt)1 / .5

=1.58-1/.5

=.58/.5

=1.16