Canucks89 said:
Can anyone give me any help on how to do this question?
dx/dt = 1-3x, where x(-1)=2
\(\displaystyle \frac{dx}{1-3x}\, = \, dt\)
Integrating
\(\displaystyle ln(1-3x)\, - \, ln(C)= \, t\)
\(\displaystyle 1- 3x \, = \, C\cdot e^t\)
Applying boundary value
\(\displaystyle 1- 3\cdot 2 \, = \, C\cdot e^{-1}\)
\(\displaystyle C\, = \,-5\cdot e\)
\(\displaystyle x \, = \, \frac{1}{3}\cdot \, (5\cdot e^{(t+1)} \, + 1)\)