August 2009 integrated algebra regents exam

Carlos.Aponte

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Hello, my name is Carlos. I had a question on my regents that I was very confused about. Please if you know how to answer this question may you please answer it. Thank you and here is the question:

What are the roots of the equation x squared - 7x + 6 =0?
A) 1 and 7
B) -1 and 7
C) -1 and -6
D) 1 and 6
 
Re: August 2009 intergrated algebra regents exam

Denis said:
Carlos.Aponte said:
What are the roots of the equation x squared - 7x + 6 =0?
A) 1 and 7
B) -1 and 7
C) -1 and -6
D) 1 and 6
x^2 - 7x + 6 = 0 ; factor to get: (x - 6)(x - 1) = 0

Go learn all about it:
http://www.google.ca/search?hl=en&s...n+factoring&btnG=Google+Search&meta=&aq=f&oq=

Well I do understand how to factor (x - 6)(x - 1) which i well get x^2 - 7x + 6
what i want to know what is the answer from all four of the multiple choices, it is asking what are the roots of the equation x^2 - 7x + 6 =0? and the roots are one of the multiple choice answers but which one is it?
 
Re: August 2009 intergrated algebra regents exam

Carlos.Aponte said:
Well I do understand how to factor (x - 6)(x - 1) which i well get x^2 - 7x + 6
what i want to know what is the answer from all four of the multiple choices, it is asking what are the roots of the equation x^2 - 7x + 6 =0? and the roots are one of the multiple choice answers but which one is it?
(x - 6)(x - 1) = 0 means that x - 6 = 0 and/or x - 1 = 0: so x = 6 or x = 1 ; got that?
 
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