Augumented Matrix

[Tiger-T]

1 0 0 4 ? 1000
1 2 0 0 ? 1100
0 2 3 0 ? 700
0 0 3 4 ? 600


Solve using the augmented matrix. Using X4 as the parameter.

I started by subtracting row 3 from row 4, I believe I am wrong to start there. How does the parameter work?

 

[Deleted member 4993]

1       0        0        4      ? 1000
1       2        0        0      ? 1100
0       2        3        0      ? 700
0       0        3        4      ? 600

Solve using the augmented matrix. Using X4 as the parameter.

I started by subtracting row 3 from row 4, I believe I am wrong to start there. How does the parameter work?

It is not very clear what you meant by parameter.

 

[Tiger-T]

The parameter is to be 4x. I guess this means the fourth equation, or the fourth number in the first column being the x value in the fourth equation. Is it clear as mud now? for me to!

[quote="Tiger-T":21smsc3h]

1       0        0        4      ? 1000
1       2        0        0      ? 1100
0       2        3        0      ? 700
0       0        3        4      ? 600

Solve using the augmented matrix. Using X4 as the parameter.

I started by subtracting row 3 from row 4, I believe I am wrong to start there. How does the parameter work?

It is not very clear what you meant by parameter.[/quote:21smsc3h]

 

[mmm4444bot]

Is it clear as mud now?

No, it is as clear as glass.

.

x[sub:2f6vmwbv]4[/sub:2f6vmwbv] is one of the four variables in the system of equations represented by the augmented coefficient-matrix that you posted.

.

They want you to express the solutions for x[sub:2f6vmwbv]1[/sub:2f6vmwbv], x[sub:2f6vmwbv]2[/sub:2f6vmwbv], and x[sub:2f6vmwbv]3[/sub:2f6vmwbv] in terms of x[sub:2f6vmwbv]4[/sub:2f6vmwbv].

.

That makes x[sub:2f6vmwbv]4[/sub:2f6vmwbv] a parameter of the solutions (not of the system of equations). Such solutions will look something like this:

.

x[sub:2f6vmwbv]1[/sub:2f6vmwbv] = -x[sub:2f6vmwbv]4[/sub:2f6vmwbv] + 1000

.

x[sub:2f6vmwbv]2[/sub:2f6vmwbv] = 2 * x[sub:2f6vmwbv]4[/sub:2f6vmwbv] + 50

.

x[sub:2f6vmwbv]3[/sub:2f6vmwbv] = -(4/3) * x[sub:2f6vmwbv]4[/sub:2f6vmwbv] + 200

.

Your questions here indicate that you're not really paying attention to your lessons. Are you fishing for people to do your homework?