If a < b, show that a < (a+b)/2 < b. The number (a+b)/2 is called the arithmetic mean of a and b.
G greatwhiteshark Full Member Joined May 8, 2005 Messages 279 Jun 30, 2005 #1 If a < b, show that a < (a+b)/2 < b. The number (a+b)/2 is called the arithmetic mean of a and b.
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Jun 30, 2005 #2 d = b - a; then: a = b - d [1] b = a + d [2] [1] (a+b) / 2 = (b - d + b) / 2 = (2b - d) / 2 < b [2] (a+b) / 2 = (a + a + d) / 2 = (2a + d) / 2 > a
d = b - a; then: a = b - d [1] b = a + d [2] [1] (a+b) / 2 = (b - d + b) / 2 = (2b - d) / 2 < b [2] (a+b) / 2 = (a + a + d) / 2 = (2a + d) / 2 > a
G greatwhiteshark Full Member Joined May 8, 2005 Messages 279 Jun 30, 2005 #4 Two Ways I like the two different methods of solving this question.
M ~Midnight.Kitten~ Junior Member Joined Jun 27, 2005 Messages 87 Jul 8, 2005 #5 is that like..simplifying expressions?
G Guest Guest Jul 8, 2005 #6 is that like..simplifying expressions? Click to expand... The task is to prove what the problem statement said to prove. You simplify whatever you can along the way to make it look nice.
is that like..simplifying expressions? Click to expand... The task is to prove what the problem statement said to prove. You simplify whatever you can along the way to make it look nice.