Find the area of the region under the curve f(x) = x (4 - x^2)^1/2 between a and b. a = 0, b = 2
L Lime New member Joined Sep 8, 2006 Messages 49 Nov 14, 2006 #1 Find the area of the region under the curve f(x) = x (4 - x^2)^1/2 between a and b. a = 0, b = 2
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Nov 15, 2006 #2 \(\displaystyle \L\\\int_{0}^{2}x\sqrt{4-x^{2}}dx\) Try the substitution: \(\displaystyle \L\\u=4-x^{2}; \;\ du=-2xdx\)
\(\displaystyle \L\\\int_{0}^{2}x\sqrt{4-x^{2}}dx\) Try the substitution: \(\displaystyle \L\\u=4-x^{2}; \;\ du=-2xdx\)
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,216 Nov 15, 2006 #4 I am sorry, but if you can't see that, then you're not ready for these sorts of problems and you should see your instructor.
I am sorry, but if you can't see that, then you're not ready for these sorts of problems and you should see your instructor.