Area problem

[Booboo2012]

An LCD panel is used for a computer monitor. When rounded to the nearest inch, the length of the monitor is16 inches and the width is 12 inches. Which of these cannot be the area of the monitor?

[1] 174 sq. in [3] 192 sq. in.
[2] 186 sq. in. [4] 204 sq. in

 

[gortwell]

if, to nearest inch, length of monitor is 16", what are the minimum and maximum lengths of monitor?
Do the same for width.

I'm sure you'll be able to continue once you have done this.

 

[yomamas]

An LCD panel is used for a computer monitor. When rounded to the nearest inch, the length of the monitor is16 inches and the width is 12 inches. Which of these cannot be the area of the monitor?

[1] 174 sq. in [3] 192 sq. in.
[2] 186 sq. in. [4] 204 sq. in

Min length of monitor is 15.51 inches(rounded to 2 decimal) and min width of monitor is 11.51 inches which means the min area is 15.51 in * 11.51 in = 178.52 sq. in that means 1 is the answer

 

[gortwell]

Min length of monitor is 15.51 inches(rounded to 2 decimal) and min width of monitor is 11.51 inches which means the min area is 15.51 in * 11.51 in = 178.52 sq. in that means 1 is the answer

min length and width are actually 15.5" x 11.5" (rounded to as many decimal points as you like). Better to try and point OP in direction of the answer, rather than do the homework for them

 

[gortwell]

Take the guidance for the OP out of it for a moment.

yomamas and gortwell,

what you discussed deals with the lower bound of the area.
Neither of you openly addressed the upper bound.

Hi lookagain

Actually, in my original reply, I did address min and max of length and width. My 2nd reply was for yomamas, not OP