Area of the Region

CatchThis2

Junior Member
Joined
Feb 6, 2010
Messages
96
I simplified 1/x to be ln(x)

I simplified 1/x^2 to be x^-2

I plugged in my limits into the equation ln(x)- (-1/x)

I got ln3 - (-1/3) - ln1 +1

My final answer is ln2 + 2/3 which is incorrect.

Can anyone see where I have gone wrong.
 
1) We don't have the whole problem. Is there a figure? Are we looking for an area between two curves?
2) "simplified"? What do you mean? Are you finding the antiderivative? No one calls that "simplified".

So, what is the problem statement?
 
ln(3) - ln(1) is NOT ln(2).

Do it again and be more careful. You seem to be close.
 
I get 1.0986 + 2/3


Is this the right answer?

This is due in an hour so I am pressed for time.
 
I wish you had gotten better at communicating before it wa too late. We were close on this one.

If we were evaluating what I think:

\(\displaystyle \int_{1}^{3}\frac{1}{x}-\frac{1}{x^{2}}\;dx\;=\;ln(3) - \frac{2}{3}\)
 
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