Area of a triangle proof

Try drawing a triangle with its base on the x-axis, and a vertex at the origin. You might then proceed by cases.

The simplest case will be a right triangle with the height line on the y-axis. Then the other side has equation y = -(h/b)x + h, where "h" is the height and "b" is the length of the base. Use a basic "integral as area" argument.

Then consider a triangle with its "peak" vertex above the segment on the x-axis which is the base. You can split this into two right triangles, and thus two integrals, similar to the first case.

And so forth.

Eliz.
 
:D Thanks a lot Eliz I got it, I just never thought of using (h/b) as the slope but it made a lot of sense right away. Thanks!
 
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