area of a hexagonal pyramid

J

juliarules

New member
Joined
May 2, 2007
Messages
6
finals are tomorrow so i need help with this really soon.

I know that y=25 after using the Pythagorean theorem, but I don't know how to find x. Please help.


math.jpg
 
Because this is a right triangle: we can apply right-triangle trig methods to find the angle X. use a trig function.

Lets use sine:

Sine(x) = opp/hyp
Sine(x) = 24/25

now use the inverse sine function to find the angle:

\(\displaystyle \L sine^{-1}(24/25)\)

X = 73.73 degrees
 
juliarules said:
finals are tomorrow so i need help with this really soon.

I know that y=25 after using the Pythagorean theorem, but I don't know how to find x. Please help.


math.jpg
Click to expand...

Your subject line indicated that this was the "area of a hexagonal prism." Sorry, but I don't see anything in your statement of the problem which indicates this.

That said, you are trying to find the measure of the angle which is marked as "x degrees;" this is a right triangle, so remember that the tangent of an acute angle in a right triangle is the ratio of the opposite leg to the adjacent leg.

So,
x = the angle whose tangent is (24/7)

x = tan<sup>-1</sup> (24/7)

Use your calculator.

If I have mis-interpreted your question, please repost, giving all details of what you have done to try to solve the problem.
 
oh yeah, sorry about the subject, i was going to put a problem about a hexagonal pyramid but changed my mind and forgot to change the subject.
 
i am still confused. How did you get 24/25 or 24/7 and do i divide that and then press the tan button on my calculator? Or do I use the sin button? :(
 
Learn your trig functions.

I gave you the solution using sin = opp/hyp
Mrspi gave you the solution using tan = opp/adj

do the inverse of one of them...but dont get them mixed up!
 
You must log in or register to reply here.
Top