How do i use integration to find the area of
\(\displaystyle f(x) = -2{\sqrt3} + {\sqrt {16 - (x-2)^2}}\)
It ranges from 0 to 4 on the x-axis.
I don't know how else to explain it, the whole problem is finding the area of a bulged triangle, and the bulge is that formula.
\(\displaystyle f(x) = -2{\sqrt3} + {\sqrt {16 - (x-2)^2}}\)
It ranges from 0 to 4 on the x-axis.
I don't know how else to explain it, the whole problem is finding the area of a bulged triangle, and the bulge is that formula.