Approximation Help Please: Consider ∫ [4 to 9] (1/√x) dx 1); Find n for which...
[FONT="]Consider ∫ [4 to 9] (1/√x) dx [/FONT]
[FONT="]1) Find a value of n for which |Ln − Rn| ≤ 0.1 [/FONT]
[FONT="]2) Use that value of n to find Ln and Rn. [/FONT]
[FONT="]3) If you take the average of the left- and right-hand sums, will your approximation be larger than the integral, or smaller? [/FONT]
[FONT="]4) Compare your numerical approximations to the answers you get using the Fundamental Theorem of Calculus.
So far this is what I have so far:
The difference of areas is Ln-Rn = [(b-a)/n](F(a)-f(b))Ln-Rn = (b-a)/n•(f(a)-f(b))
Then I got: f(a) - f(b) = 1/6•f(a)-f(b) = 1/6 & b-a =5
5/6(1/n) [/FONT][FONT="]≤ 1/10
[/FONT][FONT="]so n = 9
[/FONT][FONT="]
But I don't know how to solve #2 & #3.[/FONT]
[FONT="]Consider ∫ [4 to 9] (1/√x) dx [/FONT]
[FONT="]1) Find a value of n for which |Ln − Rn| ≤ 0.1 [/FONT]
[FONT="]2) Use that value of n to find Ln and Rn. [/FONT]
[FONT="]3) If you take the average of the left- and right-hand sums, will your approximation be larger than the integral, or smaller? [/FONT]
[FONT="]4) Compare your numerical approximations to the answers you get using the Fundamental Theorem of Calculus.
So far this is what I have so far:
The difference of areas is Ln-Rn = [(b-a)/n](F(a)-f(b))Ln-Rn = (b-a)/n•(f(a)-f(b))
Then I got: f(a) - f(b) = 1/6•f(a)-f(b) = 1/6 & b-a =5
5/6(1/n) [/FONT][FONT="]≤ 1/10
[/FONT][FONT="]so n = 9
[/FONT][FONT="]
But I don't know how to solve #2 & #3.[/FONT]
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