applied mathematics

hot stuff

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The concrete contractor is pouring a parking area at a house on HGTV. The area is 30’ X 30’ and the concrete has to be 8” thick to support the weight of the automobiles. How many yd3 of cement will the contractor have to order (round your answer up to whole yd3?
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Hello, hot stuff!

Do you know anything about inches-feet-yards?
Do you know anything about the volume of a "box"?


The concrete contractor is pouring a parking area at a house on HGTV.
The area is 30’ X 30’ and the concrete has to be 8” thick to support the weight of the automobiles.
How many cubic yards of cement will the contractor have to order?
(Round your answer up to whole cubic yard.)
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The volume is: .\(\displaystyle \text{Length} \times \text{Width} \times \text{Height}\)

. . . . . . . . . \(\displaystyle =\; \text{30 feet} \times \text{30 feet} \times \text{8 inches} \)

. . . . . . . . . \(\displaystyle =\;\text{10 yards} \times \text{10 yards} \times \frac{2}{9}\text{ yards} \)

. . . . . . . . . \(\displaystyle =\;\dfrac{200}{9}\text{ cubic yards}\)

. . . . . . . . . \(\displaystyle =\;22\frac{2}{9}\text{ cubic yards}\)

. . . . . . . . . \(\displaystyle \approx\;23\text{ cubic yards}\)
 
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