Applications of applied differentiation

joy08

New member
Joined
Dec 31, 2007
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12
I think I made an mistake through this problem: find all extrema in the interval [0,2pi] if y=x + sin x
This is what I did:
y'= 1+cos (x)
y'=o
cos x =-1
x=pi
y''=-sinx y''pi=0
x=pi
no extrema between 0 and 2pi
x=o and x=pi
 
You found y' = 0 when x = pi. You found y"(pi) = 0 so you cannot tell whether it is a relative maximum or minimum or neither. You will have to resort to the first derivative test to determine that.

Recall that if x = c is a critical point where f'(c) = 0 and f"(c) exists , then f(x) at x = c has :
- a relative maximum if f"(c) < 0
- a relative minimum if f"(c) > 0
- if f"(c) = 0, you cannot conclude anything out of the test

This is the second derivative test.
 
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