An open top rectangular tank has a volume 9 cm3.
i) If the base of the tank has a dimension where the length is twice its width, show that the total surface area, A, of the tank is A = 2x2 + 27 / x.
ii) Find the dimensions of the tank for the surface area A to be minimum.
I'm confused with this question. I'm not sure, do i need to find one more equation then compare it with A = 2x2 + 27 / x equation. Please help me?
i) If the base of the tank has a dimension where the length is twice its width, show that the total surface area, A, of the tank is A = 2x2 + 27 / x.
ii) Find the dimensions of the tank for the surface area A to be minimum.
I'm confused with this question. I'm not sure, do i need to find one more equation then compare it with A = 2x2 + 27 / x equation. Please help me?