S shivers20 Junior Member Joined Mar 3, 2006 Messages 68 Aug 10, 2006 #1 Please check my work. 1. Find the area of the region in the first quadrant that is bounded below by y=x^2 and above by the line y=x (upper function) - (lower function) dx = 0 to 1, (x) - (x^2) dx = (1/2x^2 - 1/3x^3) Is this correct?
Please check my work. 1. Find the area of the region in the first quadrant that is bounded below by y=x^2 and above by the line y=x (upper function) - (lower function) dx = 0 to 1, (x) - (x^2) dx = (1/2x^2 - 1/3x^3) Is this correct?
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Aug 10, 2006 #2 Yes , now apply your limits of integration.
, now apply your limits of integration.