ap calculus (I have sketch the graph)

[venialove]

I need help with this problem. I don't understand this problem

Let f be the function given by f(x) =? (x-3)
a)Sketch the graph and shade the region R enclosed by the graph of f, the x-axis, and the vertical line x=6.

b) Find the area of the region R described in part a

c)Rather than using the line x=6 as in part (a), consider the line x=w, where w can be any number greater than 3. Let A(w) be the area of the region enclosed by the graph of f, the x-axis, and the vertical line x=w. Write an integral expression for A(w).

d) Let A(w) be as in part described in part (c). Find the rate of change A with respect to w when w=6.

 

[galactus]

Do you have a graphing calculator. They just want the area under the curve from 0 to 6.

For part c, it's the same only with w instead of 6.

\(\displaystyle \int_{3}^{6}\sqrt{x-3}dx\)

Don't forget to take into account \(\displaystyle -\sqrt{x-3}\) if need be.