ap calculus: find f(x) if f"(x) = x + 2, f'(3), f(0) = -1

venialove said:
i need help finding this;
find y= f(x) if f''(x) =x +2, f'(3), f(0)= -1

If you integrate f"(x) - what do you get?
 
find f(x) if f"(x) = x + 2,f'(0)= 3 , f(0) = -1

f'(x)=.5x^2+2x+C
then this is what i did
f(x)=(1/6)x^3+x^2+Cx-1
 
venialove said:
find f(x) if f"(x) = x + 2,f'(0)= 3 , f(0) = -1

f'(x)=.5x^2+2x+C

f'(0) = 3

3 = C

f'(x) = .5 x^2 + 2x + 3

f(x) = (1/6)x^3 + x^2 +3x + A

f(0) = -1

-1 = A

f(x) = (1/6) x^2 + 3x - 1

then this is what i did
f(x)=(1/6)x^3+x^2+Cx-1
 
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