Please can you help with this. Solve the equation 3^x - 3(1 - 1/3^x) = 1 Thank you for looking.
D divine New member Joined Oct 16, 2005 Messages 3 Oct 16, 2005 #1 Please can you help with this. Solve the equation 3^x - 3(1 - 1/3^x) = 1 Thank you for looking.
R ryan_kidz Junior Member Joined Sep 11, 2005 Messages 89 Oct 16, 2005 #2 3^x - 3(1 - 1/3^x) = 1 3^x-3+3/3^x=1 since 3/3^x=1^x so 3^x+1^x=4 3^x=3 since 3=3^1 so 3^x=3^1 then x = 1
3^x - 3(1 - 1/3^x) = 1 3^x-3+3/3^x=1 since 3/3^x=1^x so 3^x+1^x=4 3^x=3 since 3=3^1 so 3^x=3^1 then x = 1
D Denis Senior Member Joined Feb 17, 2004 Messages 1,707 Oct 16, 2005 #3 Not quite, ryan...but close: divine said: Please can you help with this. Solve the equation 3^x - 3(1 - 1/3^x) = 1 Thank you for looking. Click to expand... let a = 3^x; then: a - 3(1 - 1/a) = 1 a - 3 + 3/a = 1 a - 4 + 3/a = 0 a^2 - 4a + 3 = 0 (a - 3)(a - 1) = 0 a = 3 or a = 1 3^x = 3 : x = 1 3^x = 1 : x = 0 Divine: if n^p = x, then p = log(x) / log(n) Like, if 3^p = 81, then p = log(81) / log(3) = 4
Not quite, ryan...but close: divine said: Please can you help with this. Solve the equation 3^x - 3(1 - 1/3^x) = 1 Thank you for looking. Click to expand... let a = 3^x; then: a - 3(1 - 1/a) = 1 a - 3 + 3/a = 1 a - 4 + 3/a = 0 a^2 - 4a + 3 = 0 (a - 3)(a - 1) = 0 a = 3 or a = 1 3^x = 3 : x = 1 3^x = 1 : x = 0 Divine: if n^p = x, then p = log(x) / log(n) Like, if 3^p = 81, then p = log(81) / log(3) = 4
