markbenjamin
New member
- Joined
- May 23, 2012
- Messages
- 1
Hi All. I am stumped by what must be a very simple trig differentiation question. Some kind of mental block.
A plane is flying horizontally at 3800 feet. It is heading towards a fixed point P on the ground at a constant altitude.
The angle of elevation of the plane is theta. The distance between the plane and the fixed point is s
When theta = 30 degree at what rate is the distance s between the plane and the point P changing in feet per degree?
I started by writing that sin theta = 3800/s
so s = 3800/sin 30 degrees
and s' = 3800* the differential of sin 30....but I get a change of hundreds of feet per degree. I am sure this is not so hard but I am totally stumped.
By the way the answer is 1.75 according to the key, I need to understand it though.
A plane is flying horizontally at 3800 feet. It is heading towards a fixed point P on the ground at a constant altitude.
The angle of elevation of the plane is theta. The distance between the plane and the fixed point is s
When theta = 30 degree at what rate is the distance s between the plane and the point P changing in feet per degree?
I started by writing that sin theta = 3800/s
so s = 3800/sin 30 degrees
and s' = 3800* the differential of sin 30....but I get a change of hundreds of feet per degree. I am sure this is not so hard but I am totally stumped.
By the way the answer is 1.75 according to the key, I need to understand it though.