Antiderivatives

tuansmart

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Nov 6, 2009
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Evaluate the indefinite integral: 8/x^4 + 4/15x
I know 8/x^4=-(8/3)x^-3
I need help on 4/15x. I know 4/15x is 4(15x^-1). If I put in zero it will be undefined. I don't know how to solve 4/15x. Can somebody help me?
 
\(\displaystyle \int\bigg(\frac{8}{x^{4}}+\frac{4}{15x}\bigg) \ dx \ = \ 8 \int x^{-4} \ dx+\frac{4}{15} \int x^{-1} \ dx\)

\(\displaystyle = \ -\frac{8}{3}x^{-3}+\frac{4}{15}ln|x|+C\)

\(\displaystyle Note: \ 4/15x \ = \ \frac{4x}{15}; \ 4/(15x) \ = \ \frac{4}{15x}, \ I'm \ assuming \ you \ wanted \ the \ latter.\)

\(\displaystyle Whether \ for \ emphasis \ or \ needed, \ a \ common \ courtesy \ is \ to \ use \ grouping \ symbols \ to \ avoid \ any\)

\(\displaystyle \ ambiguity.\)
 
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