ptsoccerboy
New member
- Joined
- Aug 29, 2007
- Messages
- 19
If f is the function defined by f(x) = cuberoot((x^2)+4x) and g is an antiderivative of f such that g(5) = 7, then g(1) approximately equals...?
I cant take the antiderivative of f(x) because it is way too complicated and I haven't learned how to yet for such a complicated problem. I thought g as the original function and so f(x) is the derivative of g and therefore gives the slope. So i graphed f(x) and found the slope at when g(1) and i hope i could find y from that but I haven't been able to.
It's a multiple choice question and the options are
a. -3.883
b. -3.557
c. 1.710
d. 3.557
e. 3.882
I know its not c because thats the slope.
Please help me. Thank you!
I cant take the antiderivative of f(x) because it is way too complicated and I haven't learned how to yet for such a complicated problem. I thought g as the original function and so f(x) is the derivative of g and therefore gives the slope. So i graphed f(x) and found the slope at when g(1) and i hope i could find y from that but I haven't been able to.
It's a multiple choice question and the options are
a. -3.883
b. -3.557
c. 1.710
d. 3.557
e. 3.882
I know its not c because thats the slope.
Please help me. Thank you!