Antiderivative question

[Mehgan]

I am supposed to take the antiderivative of sin2x/sinx.
First, I split the problem up into (1/sinx)sin2x.
Then I got cscxsin2x.
Then I got as the answer -cos2x(ln|cscx-cotx|)+C.
Is that right? I was a little confused while doing it.

Thanks

 

[Gene]

A simpler way is to use
sin(2x)=2sin(x)cos(x)
I suspect you went astray 'cause I don't see the answer this gives hiding in yours.

 

[Mehgan]

Thanks, I forgot about that rule! (It's double angle something, right?)

 

[Gene]

Yup, double angle formula. Algebra was a long time ago, huh? :evil:
---------------
Gene