Antiderivatives are new to me. Some seem easy to me such as:
. . .the antiderivative of x^5 is 1/6x^6
. . .the antiderivative of (3x+1) is 3/2x^2 + x
But then they get a little more difficult and I get frustrated For instance:
. . .(2x^4)/(3x^5 + 4)
My answer is (2/5x^5)/(3/6x^6 + 4x)
then (1)/(x(ln x)^2)
I know the derivative of ln x is 1/x, so the antidervative would be that backwards. I know that this would be solved by substitution, but that is what I am having trouble with. :?
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Edited by stapel -- Reason for edit: clarity
. . .the antiderivative of x^5 is 1/6x^6
. . .the antiderivative of (3x+1) is 3/2x^2 + x
But then they get a little more difficult and I get frustrated For instance:
. . .(2x^4)/(3x^5 + 4)
My answer is (2/5x^5)/(3/6x^6 + 4x)
then (1)/(x(ln x)^2)
I know the derivative of ln x is 1/x, so the antidervative would be that backwards. I know that this would be solved by substitution, but that is what I am having trouble with. :?
__________________________
Edited by stapel -- Reason for edit: clarity