antiderivative application

des4ij

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Nov 1, 2006
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A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 26 ft/s2. What is the distance covered before the car comes to a stop?

A car braked with a constant deceleration of 40 ft/s2, producing skid marks measuring 160 ft before coming to a stop. How fast was the car traveling when the brakes were first applied?

... just how... thx for help
 
first, you'll have to convert v<sub>o</sub> = 50 mph to ft/sec to get the units matched.

your velocity function is v(t) = v<sub>o</sub> - at

when the car is stopped, v(t) = 0

0 = v<sub>o</sub> - at ... solve for t.

to find the distance, you'll have to integrate the velocity function from 0 to the t-value found above.

you should get a distance of approx 103 ft.
 
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