Anti-Derivative

Yes, after you integrate. You plug in 8, not 6. 6 is your final answer.

The thing here is do not forget your integration constant.

Hence, find the 'particular' antiderivative.
 
No, that is not the antiderivative of \(\displaystyle \frac{-50}{x^{2}}\)

\(\displaystyle \int\frac{-50}{x^{2}}dx=\frac{50}{x}+C\)

Now, sub in x=8, set it equal to 6, and solve for C.

Remember, you're given the derivative. The antiderivative of the derivative takes you back to the function itself.
 
\(\displaystyle p(x) \ = \ \frac{50}{x} \ + \ C\)

\(\displaystyle p(8) \ = \ \frac{50}{8} \ + \ C = 6\) [sup:etmqgh8o]? Given[/sup:etmqgh8o]

\(\displaystyle C \ = \ 6 \ - \ 6.25 \ = \ -0.25\)

\(\displaystyle p(x) \ = \ \frac{50}{x} \ - \ 0.25\)
 
galactus said:
No, that is not the antiderivative of \(\displaystyle \frac{-50}{x^{2}}\)

\(\displaystyle \int\frac{-50}{x^{2}}dx=\frac{50}{x}+C\)

Now, sub in x=8, set it equal to 6, and solve for C.
Click to expand...

CatchThis2,

also, do not forget the "dx."

\(\displaystyle \int\frac{-50}{x^2}dx \ = \ \frac{50}{x} + C\)
 
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