anti derivative of ln(x)

bjackson11

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Oct 17, 2008
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Can someone please remind me why the antiderivative of ln(x) is xln(x) -x and not 1/x?
 
ln(x)dx\displaystyle \int ln(x)dx

If we use parts and let u=ln(x),   dv=dx,   du=1xdx,   v=x\displaystyle u=ln(x), \;\ dv=dx, \;\ du=\frac{1}{x}dx, \;\ v=x

and put it together, we get xln(x)x\displaystyle xln(x)-x

I will let you do the actual operations.
 
bjackson11 said:
Can someone please remind me why the antiderivative of ln(x) is xln(x) -x and not 1/x

When you find the derivative of 1/x - what do you get?

-1/x^2

That surely is not "ln(x)"


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