answer check

menal

New member
Joined
Apr 15, 2011
Messages
18
Determine the distance between L1=(-2,1,0)+s(1,-1,1) and L2=(0,1,0)+t(1,1,2)
:was the question

and i got the answer by finding the cross product: which was (1,1,1) so i+j+k
and then i found the vector joining the two given points (0+2)(1-1)(0-0) = (2,0,0)
and i found the vector perpendicular to the given lines: [1,1,1]/sqrt(1)
and thn got the dot product: (-2,1,0)-(0,1,0) dotproducy (1,1,1)/1
(2,0,0)*(1,1,1)/1
=(2)(0)+(3)(1)+(0)(1)=3
and my answer was 3.
is this correct?
 


I do not recognize some of your steps.

I used the method outlined by "Doctor Anthony" in Example (1) at this thread.

My result is 3/7 * sqrt(14) which is 1.6036 (rounded).

I did not double-check my work. 8-)

 
Top