Another rates/derivative word problem

tarynt1

New member
Joined
Sep 30, 2006
Messages
23
A pool with a triangular cross section is 12 feet wide, 18 feet long and 6 feet deep at the deep end. The shallow end decreases to a depth of zero. If the pool is being filled at a rate of 10 cubic feet per minute, find dh/dt when the water is 2 feet deep.

I don't know why, but my brain just can't process this information. I'd appreciate any help!
 
I'm still very confused. I'm not sure how to map out a correct diagram of the problem and what's being asked, so I don't even know how to start the problem.

I know I'm given dV/dt = 10. I know I have to write a volume equation, but I'm unsure of where to start with that.
 
Your problem is essentially the same as the one on the link, except yours is 0 at one end and 6 on the other, whereas, the pool in the link is 3 feet at one end and 10 feet deep on the other.

Your pool is easier to work with than the one in the link.
 
Top